MuHua-123
65 lines
2.5 KiB
C#
65 lines
2.5 KiB
C#
using System;
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using System.Collections;
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using System.Collections.Generic;
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using UnityEngine;
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/// <summary>
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/// 算法：根据设计点来生成边缘点
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/// 依据：???
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/// </summary>
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public class AlgorithmGenerateEdge : ModuleAlgorithm<DataPlate> {
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/// <summary> 算法：根据设计点来生成边缘点 </summary>
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public AlgorithmGenerateEdge() { }
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public override void Compute(DataPlate data) {
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data.edgePoints = new List<Vector2>();
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int maxIndex = data.designPoints.Count;
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for (int i = 0; i < maxIndex; i++) {
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DataDesignPoint designPoint = data.FindDesignPoint(i);
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DataDesignPoint nextDesignPoint = data.FindDesignPoint(i + 1);
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CreateStraightLine(data, designPoint, nextDesignPoint);
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}
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}
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public void CreateStraightLine(DataPlate data, DataDesignPoint designPoint, DataDesignPoint nextDesignPoint) {
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designPoint.edgePoints = new List<Vector2>();
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//方向，距离
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Vector2 direction = (nextDesignPoint.postiton - designPoint.postiton).normalized;
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float distance = Vector2.Distance(nextDesignPoint.postiton, designPoint.postiton);
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//求余，得商数
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int a = (int)(distance * 1000);
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int b = (int)(data.edgeSmooth * 1000);
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int quotient = Math.DivRem(a, b, out int remainder);
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//点位间距
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float segment = distance / quotient;
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Vector3 ap = designPoint.postiton;
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Vector3 bp = designPoint.leftBezier + designPoint.postiton;
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Vector3 cp = nextDesignPoint.rightBezier + nextDesignPoint.postiton;
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Vector3 dp = nextDesignPoint.postiton;
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for (int i = 0; i < quotient; i++) {
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float t = segment * i / distance;
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Vector2 position = ComputeBezier(ap, bp, cp, dp, t);
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designPoint.edgePoints.Add(position);
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}
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data.edgePoints.AddRange(designPoint.edgePoints);
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}
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/// <summary>
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///
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/// </summary>
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/// <param name="a">起点</param>
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/// <param name="b">起点的贝塞尔点</param>
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/// <param name="c">终点的贝塞尔点</param>
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/// <param name="d">终点</param>
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/// <param name="t">进度</param>
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/// <returns></returns>
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public Vector3 ComputeBezier(Vector3 a, Vector3 b, Vector3 c, Vector3 d, float t) {
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Vector3 aa = a + (b - a) * t;
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Vector3 bb = b + (c - b) * t;
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Vector3 cc = c + (d - c) * t;
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Vector3 aaa = aa + (bb - aa) * t;
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Vector3 bbb = bb + (cc - bb) * t;
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return aaa + (bbb - aaa) * t;
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}
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}
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